Originally posted by Northwester
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- 2 times the slope at the same speed MUST lead to 2 times the descent rate.
- If the speed is faster than the normal one, then the descent rate at the right slope is faster than, and at the wrong slope it is even more wrong than the slope alone can explain.
- This plane was flying a steeper approach than normal and faster than normal. There is no way for a 2 times the slope and 1.5 times the descent rate to co-exist.
- Forget about the 100m point. There is a clear straight slope (well, pretty straight), steeper than normal, from the beginning of the descent to about 200m QFE, a clear break at that point (a vertex if you will), and then another even steeper clear pretty straight slope from that point until the beginning of the pull-up.
- Look at the trinagles again. It clearly shows a more than twice the normal slope, wich combined with the faster speed leads to an even higher descent rate. Unless the "accurate fligth path" (in your words) is not that, the descent rate from 200m on was more than twice normal, and hence between 2 and 3 times.
So, if what you say is right, then the "accurate" plot is wrong. If the accurate plot is, well, accurate, then what you say is wrong.
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